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3 years ago

10

The value of x is PLEASE ANSWER FAST IM IN THE MIDDLE OF A TEST

1 answer:

kirza4 [7]3 years ago

3 0

The value of the exterior angle next to a triangle is equal to the sum of two angles of the triangle, opposite of the interior angle. In this case: Angle QRT is equal to the sum of angle RTS and angle RST. So if we put that into an equation it will look like this:

9x = 5x + (9 + x)
Now we can solve for x.
9x = 5x + 9 + x
9x = 6x + 9 (Combine like terms)
9x - 6x = 9 (transpose)
3x = 9
3x/3 = 9/3

x = 3

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Paha777 [63]

Answer:

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Step-by-step explanation:

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3 years ago

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Vinil7 [7]

Answer:

The factors of $2(x+y)^2-9(x+y)-5$ is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=> $2(x+y)^2-9(x+y)-5$

To Find:

The factors of the polynomial =?

Solution:

Lets assume k = (x+y)

Then $2(x+y)^2-9(x+y)-5$ can be written as $2k^2-9k-5$

Now by using quadratic formula

k = $\frac{-b\pm\sqrt{(b^2-4ac}}{2a}$

where

a= 2

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c= -5

Substituting the values, we get

k = $\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}$

k = $\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}$

k = $\frac{-(-9) \pm \sqrt{(81+40)}}{4}$

k = $\frac{-(-9) \pm \sqrt{(121)}}{4}$

k = $\frac{-(-9) \pm 11}}{4}$

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k = $\frac{20}{4}$ k = $\frac{-2}{4}$

$k_1 =5$ $k_2 = -\frac{1}{2}$

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Solving the RHS we get

$\frac{2}{2}(k-5)(2k+1)$

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Substituting k = x+y

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2 years ago

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Step-by-step explanation

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Round to nearest 10th is 226.2

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2 years ago

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LekaFEV [45]

Answer:

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Step-by-step explanation:

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