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Inessa05 [86]
3 years ago
10

The value of x is PLEASE ANSWER FAST IM IN THE MIDDLE OF A TEST

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0
The value of the exterior angle next to a triangle is equal to the sum of two angles of the triangle, opposite of the interior angle. In this case: Angle QRT is equal to the sum of angle RTS and angle RST. So if we put that into an equation it will look like this:

9x = 5x + (9 + x)
Now we can solve for x. 
9x = 5x + 9 + x
9x = 6x + 9          (Combine like terms)
9x - 6x = 9            (transpose)
3x = 9
3x/3 = 9/3

x = 3
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What is the coordinetes for B
ira [324]

Answer:

(-1,0)

Step-by-step explanation:

Point B is located one position to the left on the x-axis resulting in a negative x-value in the coordinate pair, and Point B is located 0 units up on the graph resulting in a y-value of 0. Therefore, (-1,0) are the coordinates.

5 0
3 years ago
Analyze the graph of a cannonball launched from the ground with an initial velocity of 144 feet per second. The cannonball reach
MrRissso [65]
We can find that the formula is:
h(t)=-16t^2 + 144t

We are told that the cannonball reaches its maximum height at t = 4.5 seconds. To find the maximum height, let's just plug this into the formula:
h(4.5) = -16(4.5)^2 + 144(4.5) = 324

The height is 324 feet. We're done!
7 0
3 years ago
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Complementary angles equal 90 degrees true or false
barxatty [35]

False, Complementary angles equal to 180 degrees and Supplementary angles equal to 360 degrees

7 0
3 years ago
Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0
3 years ago
Divide £30 between 2 people in the ratio 1:2
yuradex [85]
1+2=3.
30/3=10
10x1=10
10x2=20
So the answer would be £10:£20
And to check if it’s right £10 + £20= £30
3 0
3 years ago
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