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Mekhanik [1.2K]
3 years ago
9

Simplify this expression.

Mathematics
1 answer:
Tresset [83]3 years ago
6 0

Answer:

Step-by-step explanation:

Second option correct

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Given: Point C is the midpoint of AB¯¯¯¯¯.
suter [353]

Answer:

See proof below

Step-by-step explanation:

If C is the midpoint of AB, then AC = CB

Given

AC=7x−10;

CB=3x+10

Then 7x - 10= 3x+10

Add 10 to both sides

7x-10+10 = 3x +10+10

7x = 3x + 20

7x - 3x   = 10+10

4x = 20

x = 20/4

x = 5

Get AC

AC = 7x - 10

AC= 7(5) - 10

AC = 35-10

AC = 25 (Proved)

3 0
3 years ago
Five thousand three hundred nine divided by forty three
Marizza181 [45]
123.4651163 or rounded to 123.47
4 0
3 years ago
HELP!!! Picture included :).
jasenka [17]

Answer:

(A'B'): 3 1/2 IN.

(D'E'): 2 1/2 IN.

(R'S'): 4 IN.

Step-by-step explanation:

Just slice the numbers in half

Also i took the test.

6 0
3 years ago
Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

6 0
2 years ago
a family buys a car for $20,000. the value of the car decreases about 20% each year. after 6 years, the family decides to sell t
Neporo4naja [7]
No, the car is losing value not gaining it.
7 0
3 years ago
Read 2 more answers
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