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Arte-miy333 [17]
3 years ago
9

Which inequality statement best represents the graph below?

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0
Graph A is correct.  The ≥ sign is correct because the gray area is above the red.  x^2 has a positive coefficient which corresponds to the opening-up parabola.
Aneli [31]3 years ago
5 0

Answer:

Option A.

Step-by-step explanation:

(1) The given graph is a parabola, opening upwards. So coefficient of highest degree term of the function will be positive. [ f(x) = +ax² + bx + c where a > 0 ]

(2) Since parabola has been graphed by a solid line so there will be the sign of "equality". [ f(x) = ax² + bx + c ]

(3) Colored part is below the parabola so there will be an inequality showing "less than notation." [ f(x) < ax² + bx + c ]

therefore, from the given options option (A) f(x) ≤ x² - x - 1 is the answer.

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Step-by-step explanation:

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A square has side length (x+5) units. What is it’s area
daser333 [38]

The area of square is x^{2}+10 x+25 square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

\text {Area of square }=\mathrm{a}^{2}

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

\text {Area of square }=(x+5)^{2}

{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}

\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}

Thus the area of square is x^{2}+10 x+25 square units

7 0
3 years ago
Express 60 as the product of its prime factors in ascending order and give your answer in index form
Allisa [31]

Answer:

{2}^{2}, 3, 5 are the prime factors of 60.

Step-by-step explanation:

60 = 2 \times 2 \times 3 \times 5 \\  =  {2}^{2}  \times 3 \times 5 \\

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Find the highest common factor of 120 and 150
Thepotemich [5.8K]
The highest common factor is 13
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