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Arte-miy333 [17]
3 years ago
9

Which inequality statement best represents the graph below?

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0
Graph A is correct.  The ≥ sign is correct because the gray area is above the red.  x^2 has a positive coefficient which corresponds to the opening-up parabola.
Aneli [31]3 years ago
5 0

Answer:

Option A.

Step-by-step explanation:

(1) The given graph is a parabola, opening upwards. So coefficient of highest degree term of the function will be positive. [ f(x) = +ax² + bx + c where a > 0 ]

(2) Since parabola has been graphed by a solid line so there will be the sign of "equality". [ f(x) = ax² + bx + c ]

(3) Colored part is below the parabola so there will be an inequality showing "less than notation." [ f(x) < ax² + bx + c ]

therefore, from the given options option (A) f(x) ≤ x² - x - 1 is the answer.

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Which is equivalent to 12(323)?
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Solve for m 1/C+1/m=1/z
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Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

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zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
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