Answer:
Siw's age is 10 years old
Mona's age is 8 yers old
Mother's age is 40 years old
Step-by-step explanation:
Let
x ----> Siw's age
y ---> Mona's age
z ---> Mother's age
we know that
Siw is a fourth as old as mother
so
----> equation A
Mona is a fifth as old as mother
so
----> equation B
Mother is 22 years older than the two girls together.
so
----> equation C
substitute equation A and equation B in equation C

solve for z
Multiply by 20 both sides to remove the fraction


Find the value of x

Find the value of y

therefore
Siw's age is 10 years old
Mona's age is 8 yers old
Mother's age is 40 years old
<span>49:
28/2=14
42/3=14
56/4=14
49=7^2</span>
180 is the least common multiple.
Answer:
A
Step-by-step explanation:
(X) =x3 to the function q(x-6)3-4