Answer:
The probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.
Step-by-step explanation:
Let <em>X</em> = number of students arriving at the 10:30 AM time slot.
The average number of students arriving at the 10:30 AM time slot is, <em>λ</em> = 3.
A random variable representing the occurrence of events in a fixed interval of time is known as Poisson random variables. For example, the number of customers visiting the bank in an hour or the number of typographical error is a book every 10 pages.
The random variable <em>X</em> is also a Poisson random variable because it represents the fixed number of students arriving at the 10:30 AM time slot.
The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.
The probability mass function of <em>X</em> is given by:
Compute the probability of <em>X</em> = 2 as follows:
Thus, the probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.
What is the intersection of the three sets: A = {0, 2, 3, 6, 8}, B = {2, 3, 6, 8, 9}, and C = {1, 2, 4, 8, 9}? A. {2, 8, 9} B. {
Ugo [173]
Answer:
{2,8}
Step-by-step explanation:
This is the same thing as asking what element (in this case what number) is in all 3 sets.
0 isn't in all 3 sets because it isn't in B.
2 is in all 3 sets
3 isn't because it isn't in C
4 isn't in A.
6 isn't in C.
8 is in all 3 sets.
9 isn't in A
So the elements that are in the 3 sets are {2,8}.
Step-by-step explanation:
Sam, Raj and Jade have 12 sweets each
(one person has 12 sweets)
Sam has 12 sweets
one quarter of Sam sweet is blue
1/4 = one quarter
1/4 * 12 = 3
Sam has 3 blue sweets.
Answer:
yes
Step-by-step explanation: