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3 years ago

How to answer the first question

Mathematics

1 answer:

Triss [41]3 years ago

7 0

The perimeter is the outside of the shape, or in other words the total length of the sides. So if you count the total number of sides you get a perimeter of 16 units (assuming one block length is one unit)

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What is -90>-5(k-3)?

Galina-37 [17]

s=12x4+2.5/x

you do it easy

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3 years ago

PLEASE HELP!! WILL GIVE BRAINLIEST

Colt1911 [192]

Answer:

-3

Step-by-step explanation:

Given the points, we can see that as x increases by 4, y decreases by 4, which means the slope is -1. Working backwards from (5, -8), we can decrease x by 5 (and thus increase y by 5, since we're subtracting a negative) and add that to -8 to find the y-intercept = -3

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3 years ago

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Which of the following is a perfect cube? 4 8 9 12

vichka [17]

<span>Out of those, 8 is the one that is a perfect cube. </span>

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3 years ago

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A 17-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground feet

artcher [175]

Answer:

15 feet..

taking base as 8m

Given: ladder = 17 m and base = 8 m

The ladder forms a right triangle with the base of 8 m, the wall will be 15 m and the ladder (hypotenuse) is 17 m.

Let’s say you did not know that this was a standard 8–15–17 right triangle.

This is how you can figure it out:

hypotenuse(h)22 = side2112 + side2222

Let side11 = base and side22 = wall

1722 = 822 + wall22

wall = 172−82−−−−−−−√172−82

wall = 289−64−−−−−−−√289−64

wall = 225−−−√225

wall = 15 feet

5 0

3 years ago

A population of bacteria is growing exponentially. At 7:00 a.m. the mass of the population is 12 mg. Five hours later it is 14 m

sergejj [24]

Answer with Step-by-step explanation:

The exponential growth function is given by

$N(t)=N_oe^{mt}$

where

$N(t)$ is the population of the bacteria at any time 't'

$N_o$ is the population of the bacteria at any time 't = 0'

'm' is a constant and 't' is time after 7.00 a.m in hours

Assuming we start our measurement at 7.00 a.m as reference time t = 0

Thus we get $N(0)=N_oe^{m\times 0}\\\\12=N_o$

Now since it is given after 5 hours the population becomes 14 mg thus from the above relation we get

$12\times e^{m\times 5}=14\\\\e^{5m}=\frac{14}{12}\\\\m=\frac{1}{5}\cdot ln(\frac{14}{12})\\\\m=0.031$

Thus the population of bacteria at any time 't' is given by

$N(t)=12e^{0.031t}$

Part a)

Population of bacteria after another 5 hours equals the population after 10 hours from start

$N(10)=12e^{0.031\times 10}=16.361mg$

Part b)

Population of bacteria at 7:00 p.m is mass after 12 hours

$N(1)=12e^{0.031\times 12}=17.41mg$

Part c)

Population of bacteria at 8:00 p.m is mass after 1 hour

$N(1)=12e^{0.031\times 1}=12.3378mg$

Part d)

Differentiating the relation of population with respect to time we get

$N'(t)=\frac{d(12\cdot e^{0.031t})}{dt}\\\\N'(t)=12\times 0.031=0.372e^{0.031t}$

Thus we can see that the percentage increase varies with time initially the percentage increase is 37.2% but this percentage increase increases with increase in time

Part 4)

Since there are 24 hours in 1 day thus the percentage increase in the population is

$\frac{N(24)-N_o}{N_o}\times 100\\\\=\frac{25.25-12}{12}\times 100=110.42$

Thus there is an increase of 110.42% in the population each day.

7 0

4 years ago