If a polynomial "contains", in a multiplicative sense, a factor 
, then the polynomial has a zero at 
.
So, you polynomial must contain at least the following:
If you multiply them all, you get
Now, if you want the polynomial to be zero only and exactly at the four points you've given, you can choose every polynomial that is a multiple (numerically speaking) of this one. For example, you can multiply it by 2, 3, or -14.
If you want the polynomial to be zero at least at the four points you've given, you can multiply the given polynomial by every other function.
Answer:
145/2
Step-by-step explanation:
d=[2x+1-x] = [5x+1 -(2x+1)]
x+1=3x
x-3x=-1
-2x=-1
x=1/2
therefore first term is 1/2
second term is 2(1/2)+1= 2
common difference d is 2-1/2=3/2
sum of first n terms is n/2 [2a+(n-1)d] where n=10
sum of first 10 terms= 10/2[2×1/2+(10-1)3/2]
=5[1+(9)3/2] =5[1+27/2] = 5[29/2] =145/2
Answer:
It will take him roughly 4 hrs
Step-by-step explanation:
Answer: 3 and 4
Step-by-step explanation: I took the quiz
The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.
<h3>Is the equation in the image correct or incorrect?</h3>
For a quadratic equation of the form:
By using the Bhaskara's formula, the solutions of the equation:
Are given by the formula:
Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.
So the equation shown in the image is incorrect.
If you want to learn more about quadratic equations:
brainly.com/question/1214333
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