Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
It would be, 6.72/3 = $2.24
Answer:
13/3 -3i
Step-by-step explanation:
(3i-2/3)-(6i-5)
Distribute the minus sign
(3i-2/3)-6i+5
Combine like term
-2/3 +5 +3i - 6i
-2/3 +15/3 -3i
13/3 -3i
This is standard form
Answer:
5
Step-by-step explanation:
a²+b²=c²
In this case c is 13 and b is 12
a²+12²=13³
a²+144=169
Subtract 169 and 144 to find a
169-144=25
The square root of 25 is 5
