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sammy [17]
3 years ago
15

Se desea construir un parque con forma de sector circular con un radio de 402 pies y un ángulo central de 45°. ¿Cuál será la sup

erficie ocupada por dicho parque?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

63462 pies

Step-by-step explanation:

De la pregunta anterior, debemos encontrar el área del sector

La fórmula se da como:

θ / 360 × πr²

Dónde:

θ = 45 °

radio = 402 pies

Área del sector =

45/360 × π × 402²

= 63461.742399 pies

Aproximadamente el área de la ocupada por el parque = 63462 pies

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Answer:

6.5

Step-by-step explanation:

plz mark brainlyest

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3 years ago
Please help! what is an equation of a parabola with x-intercepts at (2,0) and (-7,0) and which passes through the point (1,32)?​
Vika [28.1K]

Answer:

<h3>            f(x) = - 4x² - 20x + 56  </h3>

Step-by-step explanation:

f(x) = a(x - x₁)(x - x₂)     - factored form of the equation of the parabola with zeros x₁ and x₂

x-intercepts at (2,0) and (-7,0) means zeros: x₁=2 and x₂=-7

So:

f(x) = a(x - 2)(x + 7)     - factored form of the equation of the parabola with x-intercepts at (2,0) and (-7,0)

The parabola passing through point (1, 32) means if x=1 then f(x)=32

Then:

        32 = a(1 - 2)(1 + 7)  

        32 = a(-1)(8)  

        32 = - 8a

         a = - 4

Therefore the equation of a parabola with x-intercepts at (2,0) and (-7,0) and which passes through the point (1,32):

                          <u>  f(x) = -4(x - 2)(x + 7)  </u>

Expanding to standard form:

     f(x) = -4(x - 2)(x + 7)

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8 0
3 years ago
Plzz help me solve questions 15 and 16...!!
iVinArrow [24]

15.

We have right triangles, with the ladder the hypotenuse of both and the wall the opposite side of both.

Call the ladder length <em>h.</em>

Against the wall we have the opposite of alpha the taller one:

q = h \sin \alpha - h \sin \beta

On the ground adjacent to beta is the longer one

p = h \cos \beta - h \cos \alpha

Dividing

\dfrac p q = \dfrac{  h \cos \beta - h \cos \alpha }{h \sin \alpha - h \sin \beta} =  \dfrac{ \cos \beta -\cos \alpha }{\sin \alpha - \sin \beta} \quad\checkmark

16.

Again I'm too lazy to draw the figure but you should.

Let's call <em>y </em>the height of the tower and <em>x</em> the distance from the observation point on the ground to the base of the tower.

\tan 60^\circ = \dfrac y x

\tan 30^\circ = \dfrac{y - 40}{x}

Since \sin 30 =\cos 60 = \frac 1 2 \textrm{ and } \cos 30 = \sin 60 = \sqrt{3}/2

\tan 60^\circ = \sqrt{3} = y/x

\tan 30^\circ = 1/\sqrt{3} = (y-40)/x

Dividing,

\sqrt{3}/ (1/\sqrt{3}) = (y/x) / ((y-40)/x)

3 = y/(y-40)

3y - 120 = y

2y = 120

y = 60

x = y/\sqrt{3} = 60(\sqrt{3}/3) = 20 \sqrt{3}

Answer: Height 60 meters, distance 20√3 meters

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3 years ago
What is the greatest common factor of 364 and 585?
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3 years ago
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Answer for brainliest and 10 points
umka2103 [35]

Answer:

It is rational because 121 is a perfect square.

7 0
3 years ago
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