Answer: See attached table
Step-by-step explanation:
+---+---+---+
| 1 | 8 | 2 |
+---+---+---+
| 6 | 4 | 2 |
+---+---+---+
| 5 | 0 | 7 |
+---+---+---+
<u>Proofs:</u>
First row: 1+6+5 = 12
Second row: 8+4+0 = 12
Third row: 2+2+7 = 12
First column: 1+8+2 = 12
Second column: 6+4+2 = 12
Third column: 5+0+7 = 12
Diagonal starting from top left to bottom right: 1+4+7 = 12
Diagonal staring from top right to bottom left: 2+4+5 = 12
Answer:
P = 9 is the max value
Step-by-step explanation:
Sketch
2x + 4y = 10
with x- intercept = (5, 0) and y- intercept (0, 2.5)
x + 9y = 12
with x- intercept = (12, 0) and y- intercept = (0, )
Solve
2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)
The region corresponding to the solution of the system of constraints
Has vertices at (0, ), (0, 0) , (5, 0) and (3, 1)
Now evaluate the objective function at each vertex.
(0, 0) can be excluded as it will not give a maximum
(5, 0) → P = 5 + 0 = 5
(0, ) → 0 + 8 = 8
(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value
Thus the maximum value is 9 when x = 3 and y = 1