Please help I’m really lost. This is my final hw.

Y=5/2x-19 and 5x+2y=-8 a perpendicular,parallel or intersecting lines?

dimaraw [331]

Answer:

There intersecting lines

Step-by-step explanation:

5x+2y=-8

-5x -5x

2y=-8 -5x

/2 /2 /2

y=-4 -5/2x also

y=-5/2x - 4

&

y=5/2x - 19

neither parallel (slope is not the same)

or perpendicular (slope is not reciprocal or opposite signed)

hope i helped

6 0

3 years ago

The women'schorus has 33members. How many quartetscan be formed? How many singers will be left over?

andreyandreev [35.5K]

Answer: 8 quartets can be formed.

1 singer will be left over.

Step-by-step explanation:

A quartet is a group of 4 members.

Given: The women'schorus has 33 members.

The number of quartets can be formed = (Total members) divided by (4)

= 33 ÷ 4

By solving 33 ÷ 4 we get 8 as quotient and remainder as 1 such that

33 = 4 x 8 +1

Hence, 8 quartets can be formed.

1 singer will be left over.

8 0

3 years ago

Which is a factor of 15xy − 45x − 6y + 18?

Nadya [2.5K]

The factor of <span>15xy − 45x − 6y + 18 is 3(y-3)(5x-2).</span>

8 0

3 years ago

Read 2 more answers

Name the plane that is highlighted in the diagram below

larisa86 [58]

The plane that is highlighted inside the given cuboid is called a Rectangle.

<h3>What is the Plane in the given solid?</h3>

A cross-section is the intersection of a solid and a plane. Plane Figures and defined as solid shapes.

In geometry, shapes are the forms of objects which have boundary lines, angles and surfaces. These figures demonstrate the shape of objects we see in our everyday lives. There are different types of 2D shapes and 3D shapes. The plane shapes are two-dimensional closed shapes with no thickness and are known as 2D shapes.

Solid shapes are nothing but solids with three dimensions: length, breadth, and height. Solid shapes are also known as 3D shapes.

Now, looking at the given figure we see that it is a cuboid and we see that the 2 dimensional plane cut through it is clearly a rectangle.

Thus, we can conclude that the plane that is highlighted inside the given cuboid is called a Rectangle.

Read more about Plane in Solid at; brainly.com/question/1609720

#SPJ1

3 0

1 year ago

Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com

Rasek [7]

Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.9842

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 183 - 4 = 179 pounds.

The upper end of the interval is the sample mean added to M. So it is 183 + 4 = 187 pounds.

The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.9842\frac{23}{\sqrt{100}} = 4.6$

The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

The upper end of the interval is the sample mean added to M. So it is 190 + 4.6 = 194.6 pounds.

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

7 0

3 years ago