(-5, 12). Cosecant is the reciprocal of sine. Since csc theta =13/12, sin theta=12/13. We can narrow down to two angles, one in first quadrant and one in second quadrant. We are also given sec theta=-13/5, so cos theta=-5/13. Thus the angle is in the second quadrant. tan theta=1/cot theta=-12/5, so point (-5, 12) is on the ray.
Answer: 10x^3 hope that is correct
First find the slope of the given line like this:

If two lines are parallel, then they have the same slope, so the equation we are looking for is in the form:

and we have to find b using the given point like this:
Substitute x = -2 and y=4 in the above equation like this and solve for a:
The equation of the line is then the following:
First you plug in for x,
2(y-3)+y=12
Then you solve for y
2y-5+y=12
-10y+y=12
-9y=12
-9y/9=12/-9
y=-1.333333333333333333333333333333333333333333333333333333333