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3 years ago

In AKLM, mZK = 101° and mL = 67º. Which statement about the sides of AKLM

Mathematics

1 answer:

Iteru [2.4K]3 years ago

3 0

Answer:

LM > MK > KL

Step-by-step explanation:

Given: ΔKLM , m∠K = 101° , m∠L = 67°

By definition of a triangle's sum of interior angles, the ∑ΔKLM's interior angles is 180°, ∴ m∠M = 180 - (101 + 67) = 12°

By the usage of law of sines, the opposite side's measurement is contingent with the angle measurement. The smaller the angle measurement, the shorter the opposite side.

Note the angles:

m∠M = 12° ∴ Side LK = shortest

m∠K = 101° ∴ Side ML = longest

m∠L = 67° ∴ Side KM = in between

∴ LK < KM < ML

A) LM > MK > KL is your answer.

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Morgarella [4.7K]

Answer:

Step-by-step explanation:(a)

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3 years ago

Read 2 more answers

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aleksandrvk [35]

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3 years ago

20% of Ms. Martin's class did not complete their homework. If there are 30 students in her class, how many did not complete home

padilas [110]

Answer:

Step-by-step explanation:

20% of 30 is 6

Words: 6 Students in Ms. Martin's class did not do their homework.

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3 years ago

Using the 3 functions below, make the desired transformation(s) to the correct function and describe the transformation(s). Writ

Eduardwww [97]

Answer:

The transformation of $g(x)$ to $k(x)$ consists in a vertical translation. The new equation is $k(x) = -12\cdot x-6$ .

Step-by-step explanation:

Let $g(x) = -12\cdot x - 3$ . We proceed to make the required transformations on $g(x)$ , which consists in one vertical translation, 3 units in the -y direction. That is to say:

$k(x) = g(x) - 3$ (1)

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3 years ago

Anyone know how to do area or volume? Any help will do! thanks

exis [7]

Answer:

Volume: x(x+6)(x+2) Area: $x^{2}$ + 8x +12

Step-by-step explanation:

Volume Explanation:

To find the volume of a 3d figure, we must multiply the length, width, and the height. Therefore we multiply (x)(x+6)(x+2)= $x^{3}$ + 8 $x^{2}$ + 12x. Simplify this equation and we will get x(x+6)(x+2) for the formula to find the volume of the 3D figure.

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2 years ago