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irina [24]
3 years ago
13

While visiting New Orleans, Kyla and a friend decided to rent a Tandem Bike to explore City Park. Wheel Fun Rentals charges $8.5

0 per hour in addition to a $25.00 deposit to rent the bike. If they rented the bike from 11:30 a.M. Until 3:30 p.M., write and solve a linear equation to find the total cost to rent the bike.
Mathematics
1 answer:
german3 years ago
4 0
Let C represent the total cost, and H represent the number of hours...
C = $25 + $8.50(H)
So for this problem...
C = $25 + $8.50x4
C = $25 + $34
C = $59
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Determine whether the equation x^3 - 3x + 8 = 0 has any real root in the interval [0, 1]. Justify your answer.
nikdorinn [45]

Answer:

The equation does not have a real root in the interval \rm [0,1]

Step-by-step explanation:

We can make use of the intermediate value theorem.

The theorem states that if f is a continuous function whose domain is the interval [a, b], then it takes on any value between f(a) and f(b) at some point within the interval. There are two corollaries:

  1. If a continuous function has values of opposite sign inside an interval, then it has a root in that interval. This is also known as Bolzano's theorem.
  2. The image of a continuous function over an interval is itself an interval.

Of course, in our case, we will make use of the first one.

First, we need to proof that our function is continues in \rm [0,1], which it is since every polynomial is a continuous function on the entire line of real numbers. Then, we can apply the first corollary to the interval \rm [0,1], which means to evaluate the equation in 0 and 1:

f(x)=x^3-3x+8\\f(0)=8\\f(1)=6

Since both values have the same sign, positive in this case, we can say that by virtue of the first corollary of the intermediate value theorem the equation does not have a real root in the interval \rm [0,1]. I attached a plot of the equation in the interval \rm [-2,2] where you can clearly observe how the graph does not cross the x-axis in the interval.  

6 0
2 years ago
at tennis practice, tim practices his backhand and his serve at least 2 hours each day. He works less on his backhand than his s
earnstyle [38]
For the answer to the question above, Tim practices his backhand and his serve at least 2 hours each day this means X =< 2 ( less than or equal to 2 hrs). He works less on his backhand than his serve and practices his serve more than an hour daily.  <span>Y < 1</span>
3 0
2 years ago
List the different names and define the characteristics of each angles
Rama09 [41]
An acute angle measures less than 90 degrees, a right angle measures 90 degrees and, obtuse angle measures more than 90 degrees
3 0
3 years ago
Lent receives per day?
Misha Larkins [42]

Answer:

Can you see my answer?

Step-by-step explanation:

Everytime i try answering it won't work. I just wanted to know if u can see this

3 0
2 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
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