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3 years ago

Evaluate please I need helppppp!!!!!!!

Mathematics

1 answer:

Inessa [10]3 years ago

5 0

Answer:

400

Step-by-step explanation:

$\bigg( \frac{5}{6} a \bigg)^{2} \\ \\ = \bigg( \frac{5}{\cancel 6} \times \cancel {24} \bigg)^{2} \\ \\ = \bigg( 5 \times 4 \bigg)^{2} \\ \\ = {(20)}^{2} \\ \\ = 400$

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PLEASE HELP THIS IS DUE TODAY

avanturin [10]

Answer:7600

Step-by-step explanation:

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3 years ago

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Y=4x-17 into standard form

Debora [2.8K]

Y-4X=-17 or -4x + y =-17

to convert it into standard from you first need to get X on the left, you can do that by subtracting x from both sides,

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4 years ago

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Find the measure of the angle θ between u and v. Express the answer in radians rounded to two decimal places, if it is not possi

zhuklara [117]

Answer:

The question is incomplete as some details are missing; Here is the complete question; If vector u = 3i and v = 4i + 4j, Find the measure of the angle θ between u and v. Express the answer in radians rounded to two decimal places, if it is not possible to express it exactly.

The measure of the angle θ between u and v = 0.785radians

Step-by-step explanation:

The detailed steps is as shown in the attachment.

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3 years ago

Use a surface integral to find the general formula for the surface area of a cone with height latex: h and base radius latex: a(

BlackZzzverrR [31]

We can parameterize this part of a cone by

$\mathbf s(u,v)=\left\langle u\cos v,u\sin v,\dfrac hau\right\rangle$

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$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=\sqrt{1+\dfrac{h^2}{a^2}}u\,\mathrm du\,\mathrm dv$

The area of this surface (call it $\mathcal S$ ) is then

$\displaystyle\iint_{\mathcal S}\mathrm dS=\sqrt{1+\frac{h^2}{a^2}}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=a}u\,\mathrm du\,\mathrm dv=a^2\sqrt{1+\frac{h^2}{a^2}}\pi=a\sqrt{a^2+h^2}\pi$

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3 years ago

Solve for x.<br><br> 7(x + 14) = -343

kvv77 [185]

7(x+14)=-343
Use distributive property
7x+98=-343
Subtract 98 for both side
7x=-441
Divided 7 for both side
x=-63. Hope it help!

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4 years ago

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