Question

-7p (p+8)=21 is equal to

Answer 1

We have the equation:

$-7p(p+8)=21$

So then we need to distribute -7p to the parentheses:

$-7p^{2}+(-56p)=21$

Then we need to set the equation equal to 0, so we must subtract 21 on both sides:

$-7p^{2}-56p-21=0$

Then we need to factor this. So we end up with:

$7(-x^{2}-8p-3)=0$

This is as much as this can be factored, so we cannot go any further.