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Kay [80]
3 years ago
8

A sample of gas is placed into an enclosed cylinder and fitted with a movable piston. Calculate the work (in joules) done on the

gas if it is compressed from 18.38 L to 7.11 L with a pressure of 2.02
Chemistry
1 answer:
Elodia [21]3 years ago
8 0

Answer:

Work done = 2307.17 j

Explanation:

Given data:

Work done = ?

Initial volume =18.38 L

Final volume = 7.11 L

Pressure = 2.02 atm

Solution:

work done = W = -PΔV

ΔV = V₂- V₁

work done = w = -P(V₂- V₁)

Now we will put the values in formula.

W = - 2.02 atm (7.11 L - 18.38 L)

W = - 2.02 atm (-11.27 L)

W = 22.77 atm.L

atm.L to joule:

22.77 atm.L × 101.325 J / 1L.atm

2307.17 j

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<u>Electrons</u>:

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4 0
1 year ago
0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction
algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

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number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

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thus 0.50 moles of A will produce 1 mole of D

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