<h3>Answer:</h3>
89.6 L of O₂
<h3>Solution:</h3>
The balanced chemical equation is as,
CH₄ + 2 O₂ → CO₂ + 2 H₂O
As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,
44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂
So,
88 g CO₂ will be produced by = X L of O₂
Solving for X,
X = (88 g × 44.8 L) ÷ 44 g
X = 89.6 L of O₂
3
Species
Genetic diversity
Ecosystem diversity
Copper II sulfate solution is blue.
Answer:
PubChem CID 16663
Structure Find Similar Structures
Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet
Molecular Formula C9H20
Synonyms 4-ETHYLHEPTANE 2216-32-2 Heptane, 4-ethyl- 4-ethyl-heptane 4-ethyl heptane
Explanation:
