One atom of an element A =6.644 *10^-23 gm. calculate the no. of gram atom in 80 kg of it.<br><br>

Why is amniocentesis a more widely used test than cvs?

maw [93]

Higher probability of loss. Chorionic villus sampling (CVS) and Amniocentesis (AC). The prenatal diagnosis technique can be done earlier in fetal development CVS (first trimester --> 10-13 weeks). AC (second trimester --> 16-20 weeks)

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4 0

3 years ago

Disadvantages of synthetic rubber

I am Lyosha [343]

Answer:

can be easily broken not as reliable as natural made rubber

8 0

3 years ago

Read 2 more answers

Does (ionic/metallic/covalent) bonds form strong or brittle chemicals? explain

NNADVOKAT [17]

These atomic properties help describe the macroscopic properties of compounds. For example, smaller covalent compounds that are held together by weaker bonds are frequently soft and malleable. ... Ionic compounds, though composed of strong bonding interactions, tend to form brittle crystalline lattices.

4 0

3 years ago

The following reaction was performed in a sealed vessel at 760 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at

zubka84 [21]

Answer:

The equilibrium constant is 273.0322

Explanation:

For the given chemical reaction ,

ICE table can be written as -

H₂(g) + I₂(g) ⇄ 2HI(g)

initial moles 3.85 2.35 -

at equilibrium 3.85 - x 2.35 - x 2x

From question , at equilibrium the concentration of I₂ = 0.0500 M

The concentration of I₂ ( ICE table ) = concentration of I₂ (given in question )

2.35 - x = 0.0500

x = 2.3

Putting the value of x in ICE table , to obtain the concentration terms as-

[H₂] = 3.85 - x

[H₂] = 3.85 - 2.3

[H₂] = 1.55 M

[HI] = 2x

[HI] = 2* 2.3

[HI] = 4.6 M

[I₂] = 0.0500M (Given)

Equilibrium Constant ( Kc )

The value of equilibrium constant is written as the concentration of the products each raised to the power of their respective stoichiometry by the concentration of reactants each raised to the power of their respective stoichiometry.

Kc = [HI]² / [H₂][I₂]

Kc = ( 4.6 )² / (1.55)*(0.0500)

Kc = 273.0322 .

6 0

4 years ago

The relationship between the molar concentration of silver ion in a saturated solution of silver phosphate and the solubility pr

kondor19780726 [428]

Answer: The solubility product of $Ag_3PO_4$ is $27s^4$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

$Ag_3PO_4\leftrightharpoons 3Ag^++PO_4^{3-}$

We are given:

Solubility of $Ag_3PO_4$ = S mol/L

By stoichiometry of the reaction:

1 mole of $Ag_3PO_4$ gives 3 moles of $Ag^{+}$ and 1 mole of $PO_4^{3-}$ .

When the solubility of $Ag_3PO_4$ is S moles/liter, then the solubility of $Ag^{+}$ will be 3S moles\liter and solubility of $PO_4^{3-}$ will be S moles/liter.

Expression for the equilibrium constant of $Ag_2CrO_4$ will be:

$K_{sp}=[Ag^+]^3[PO_4^{3-}]$

$K_{sp}=[3s]^3[s]=27s^4$

The solubility product of $Ag_3PO_4$ is $27s^4$

8 0

3 years ago

One atom of an element A =6.644 *10^-23 gm. calculate the no. of gram atom in 80 kg of it.​

One atom of an element A =6.644 *10^-23 gm. calculate the no. of gram atom in 80 kg of it.