One atom of an element A =6.644 *10^-23 gm. calculate the no. of gram atom in 80 kg of it.
1 answer:
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Taking into account the definition of calorimetry and latent heat, the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 is 1,336 kJ.
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
<h3>Latent heat</h3>Latent heat is defined as the energy required by a quantity of substance to change state.
When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.
The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to
Q = m×L
where L is called the latent heat of the substance and depends on the type of phase change.
<h3>Heat energy required to melt ice</h3>In this case, you know:
- m= 4 kg
- L= specific latent heat of fusion of water= 334,000
Replacing in the expression for latent heat:
Q = 4 kg× 334,000
Solving:
<u><em>Q= 1,336,000 J= 1,336 kJ </em></u>(being 1,000 J= 1 kJ)
Finally, the correct answer is the first option: the heat energy required to melt 4 kg of ice when the specific latent heat of fusion of water is 334,000 is 1,336 kJ.
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