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Mademuasel [1]
3 years ago
9

Us What is the percent of O in Cr2O3? (Cr = 52.00 amu, O = 16.00 amu) [? ]%

Chemistry
1 answer:
Gekata [30.6K]3 years ago
8 0

The percent of O in  Cr₂O₃ : 31.58%

<h3>Further explanation</h3>

Given

Cr = 52.00 amu, O = 16.00 amu

Required

The percent of O

Solution

MW Cr₂O₃ = 2 x Ar Cr + 3 x Ar O

MW Cr₂O₃ = 2.52+3.16

MW Cr₂O₃ =152 amu

\tt \%O=\dfrac{3.Ar~O}{MW~Cr_2O_3}\times 100\%\\\\\%O=\dfrac{3.16}{152}\times 100\%\\\\\%O=31.58\%

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Gre4nikov [31]

Answer:

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8 0
3 years ago
How do we balance a chemical equation 4 marks?.
Vesna [10]

To balance a chemical equation, place coefficient as needed in front of the symbols or formulas of the elements. So the same number of each type of atom occurs in both reactants and products.

Steps to be followed are-

(1) Write down the chemical reaction in the form of word equation, keeping all the reactants on left hand side and keeping products on right hand side.

(2) Write all the symbol and formula of all reactants and products in word equation.

(3) Balance the whole equation by multiplying the symbols and formula by smallest possible figures.

Same number of each and every atom, of same type occurs in both reactants and products.

Once all the individual elements are balanced, then the total number of atoms of each element on the reactant and product side are compared once again after balancing. If there are no inequalities, the chemical equation is said to be balanced.

To learn more about balancing chemical equations visit the link- brainly.com/question/26227625

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6 0
2 years ago
An aluminum engine block requires 8669 kJ of energy for the temperature to rise from 75.0 °F to 195 °F. The specific heat of lea
quester [9]

Answer:

The answer to your question is 144 kg

Explanation:

Data

Q = 8669 kJ

T1 = 75°F

T2 = 195°F

Cp = 0.897 J/(g°C)

m = ?

Formula

           Q = mCp(T2 - T1)

Process

1.- Convert temperature to °C

T1 = (75 - 32) / 1.8

   = 43/1.8

   = 23.9°C

T2 = (195 - 32) / 1.8

     = 163/1.8

     = 90.6°C

2.- Solve for m

            m = Q / Cp(T2 - T1)

3.- Substitution

            m = 8669000 / 0.897(90.6 - 23.9)

4.- Simplification

            m = 8669000 / 59.83

5.- Result

            m = 144893.66 g or 144.9 kg

6 0
3 years ago
Please hep its my last question
atroni [7]

Answer:Noble gases:

 are highly reactive.

 react only with other gases.

 do not appear in the periodic table.

 are not very reactive with other elements.

Explanation:Noble gases:

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 react only with other gases.

 do not appear in the periodic table.

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7 0
2 years ago
How is the orbital configuration of neutral atoms related to the atoms chemical properties
timama [110]

Answer:

Explanation:

Chemical properties of atoms relies solely on the number of electrons they contain, more particularly, the valence or outermost electrons in the orbit round the nucleus of an atom.

A neutral atom is one that has not gained or lost electron or even shared electrons with any other atom.

On close examination of how electrons are distributed in the orbits of an atom, we can know if an atom will gain or lose electrons in a reaction. This is very important in determining the chemical properties of an atom.

7 0
3 years ago
Read 2 more answers
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