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3 years ago

What is the correct balanced equation for the following equilibrium constant expression?

1 answer:

8 0

The correct answer is 3) 2CO2(g) ⇄ 2CO(g) + O2(g)

this is the correct one because it is a decomposition reaction and all the number of atoms is equal on both sides.

there are 2 C atoms on both sides.

and 4 O atoms on both sides.

and 1) the atoms numbers are equal on both sides but not correct as it not a

correct number as it has 1/2 O2.

and 2) CO2(g) ⇆ CO(g) + O2

the number of O atoms is not equal on both sides of the equation.

we have 2 O atoms on the left side and 3 O atoms on the right side.

so, this not a balanced equation.

4) also not correct 2CO(g) + O2 ⇆ 2CO2

as it is not a decomposition reaction and the 2CO & O2 are as reactants not products.

so the correct answer is 3) 2CO2(g) ⇆ 2CO(g) + O2(g)

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1. Mg2+ and Ca2+ are in the same group on the periodic table. In terms of electronic

finlep [7]

Answer:

Se detailed explanation.

Explanation:

Hello,

In this case, since both magnesium and calcium ions are in group IIA, we can review the following similar properties:

- Since both calcium and magnesium are in group IIA they have two valence electrons, it means that the both of them have two electrons at their outer shells.

- They are highly soluble in water when forming ionic bonds with nonmetals such as those belonging to halogens and oxygen's family.

- Calcium has 18 electrons and magnesium 10 which are two less than the total protons (20 and 12 respectively) since the both of them have lost two electrons due their ionized form.

- Their electron configurations are:

$Ca^{20}=1s^2,2s^2,2p^6,3s^3,3p^6,4s^2\\\\Mg^{12}=1s^2,2s^2,2p^6,3s^2$

It means that the both of them are at the $s$ region since it is the last subshell at which their electrons are.

Best regards.

8 0

4 years ago

Iron (III) chloride + sodium carbonate → iron (III) carbonate + sodium chloride Which of these is the balanced equation for the

Nonamiya [84]

2 FeCl3 + 3 Na2CO3 = Fe2(CO3)3 + 6 NaCl

4 0

3 years ago

Solve the fo<br> 1. 750 mL =<br> L

Leokris [45]

759 mililitera is equal to 0.75 liter

7 0

3 years ago

Which of the following have the most similar properties?

rjkz [21]

Answer:

Option-B (Carbon and Silicon)

Explanation:

Among the given pairs only carbon and silicon have the most similar properties. This is because,

Sodium and Magnesium belong to different groups. Sodium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Magnesium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

2 Na + Cl₂ → NaCl

Mg + Cl₂ → MgCl₂

As shown in reactions when Sodium and Magnesium are treated with Cl₂ they give a products with different proportions.

Carbon and Silicon show almost same properties because both belong to Group IV hence both are capable of forming four bonds. Also, they share the same property of self linkage in making a long chains.

Argon and Chlorine also belong to two different groups. Argon is present in Group VIII (Noble Gases) and Chlorine is present in Group VII (Halogens). Hence, Argon is an inert specie which is non reactive while Chlorine gives different reaction easily.

Potassium and Calcium belong to different groups. Potassium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Calcium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

2 K + Cl₂ → KCl

Ca + Cl₂ → CaCl₂

As shown in reactions when Potassium and Calcium are treated with Cl₂ they give a products with different proportions.

6 0

4 years ago

How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution

Lelechka [254]

The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

<h3>Balanced equation </h3>

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 2
The mole ratio of the base, Ca(OH)₂ (nB) = 1

<h3>How to determine the volume of Ca(OH)₂ </h3>

Molarity of base, Ca(OH)₂ (Mb) = 1.48 M
Volume of acid, HCl (Va) = 36 mL
Molarity of acid, HCl (Ma) = 1.63 M
Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

2.96 × Vb = 58.68

Divide both side by 2.96

Vb = 58.68 / 2.96

Vb = 19.8 mL

Learn more about titration:

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6 0

2 years ago