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lbvjy [14]
3 years ago
5

What is the correct balanced equation for the following equilibrium constant expression?

Chemistry
1 answer:
weeeeeb [17]3 years ago
8 0
The correct answer is 3) 2CO2(g) ⇄ 2CO(g)  + O2(g)

this is the correct one because it is a decomposition reaction and all the number of atoms is equal on both sides.

there are 2 C atoms on both sides. 

and 4 O atoms on both sides.

and 1) the atoms numbers are equal on both sides but not correct as it not a

correct number as it has 1/2 O2.


and 2) CO2(g) ⇆ CO(g) + O2 

the number of O atoms is not equal on both sides of the equation.

we have 2 O atoms on the left side and 3 O atoms on the right side.

so, this not a balanced equation.

4) also not correct 2CO(g) + O2 ⇆ 2CO2

as it is not a decomposition reaction and the 2CO & O2 are as reactants not products.

so the correct answer is 3) 2CO2(g) ⇆ 2CO(g) + O2(g)
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Answer:

id think b but im not 100% sure if you get it wrong im sorry

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3 years ago
What would be the change in pressure in a sealed 10.0 l vessel due to the formation of n2 gas when the ammonium nitrite in 2.40
larisa86 [58]

The  change  in pressure in a sealed 10.0L vessel  is 5.28 atm

<u><em>calculation</em></u>

The pressure is calculated using the ideal gas equation

That is   P=n RT

where;

P (pressure)= ?

v( volume) = 10.0 L

n( number of moles)  which is calculated as below

<em>write the equation  for  decomposition  of   NH₄NO₂</em>

NH₄NO₂  →  N₂  +2H₂O

<em>Find the moles of NH₄NO₂</em>

 moles = molarity x volume in liters

= 2.40 l x 0.900 M =2.16 moles

<em>Use the mole ratio to determine the  moles of N₂</em>

that is from equation above  NH₄NO₂:N₂ is 1:1 therefore the moles of N₂ is also =2.16 moles

R(gas constant) =0.0821 l.atm/mol.K

T(temperature)  = 25° c  into kelvin = 25 +273 =298 K

make p the  subject of the formula  by diving both side  by  V

P = nRT/V

p ={ (2.16 moles x 0.0821 L.atm/mol.K  x 298 K) /10.0 L} = 5.28  atm.




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