1/9
Here's the proper explanation:
Since the vertex is (2,-1), the original equation will look like this: y=a*(x-2)^2-1
When the substitution happens we get to this:
0=a*(5-2)^2-1 then 1=a*(5-2)^2 -> 1=a*9
So, a=1/9! Written in another form:
1/9x^2-4/9x+4/9-1

Hope could help :)

8 0

3 years ago

What is the range of y= x + 2?

Lelu [443]

Answer:

A) all real numbers greater than or equal to 2

Domain: $x\geq 0$

Step-by-step explanation:

The variable in the radical x cannot be less than 0 as that wouldn’t be defined. So, the maximum that x can be is 0, and $y=x+2$ . So, 0+2=2, and y is greater than or equal to 2.

Domain is x is greater than or equal to 0 because you cannot square a negative. So, it must not be less than 0. It could be 0 because square root of 0 is just 0.

7 0

2 years ago

Given f(x) = 5x - 7 and g(x) = x² - 3, find f(f(2)).

sveta [45]

Step-by-step explanation:

Given f(x) = 5x - 7 and g(x) = x² - 3, find f(f(2))

4 0

2 years ago

Slope of -3 and y-intercept of 5, write an equation in slope intercept form￼

Slope of -3 and y-intercept of 5, write an equation in slope intercept form