Question

What is the theoretical mass of CO2 + H2O lost per gram of NaHCO3?

Answer 1

Answer:

The theoretical mass of CO2 = 2.09 grams

The theoretical mass of H2O =  0.429 grams

The theoretical  mass of CO2+ H2O = 2.519 grams

Explanation:

Step 1: Data given

Mass of NaHCO3 = 1 gram

Molar mass NaHCO3 = 84.00 g/mol

Molar mass of CO2 = 44.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

4NaHCO3 + O2 → 4CO2 + 2H2O + 2Na2O2

Step 3: Calculate moles of NaHCO3

Moles NaHCO3 = mass NaHCO3 / molar mass NaHCO3

Moles NaHCO3 = 1.0 gram / 84.00 g/mol

Moles NaHCO3 = 0.0119 moles

Step 4: Calculate moles CO2 and H2O

For 4 moles NaHCO3 we need 1 mol O2 to produce 4 moles CO2 and 2 moles H2O and 2 moles Na2O2

For 0.0119 moles NaHCO3 we'll have 4*0.0119= 0.0476 moles CO2

and 2* 0.0119 = 0.0238 moles H2O

Step 5: Calculate mass CO2 and H2O

Mass = moles * molar mass

Mass CO2 = 0.0476 moles * 44.01 g/mol

Mass CO2 = 2.09 grams

Mass H2O = 0.0238 moles ¨18.02 g/mol

Mass H2O = 0.429 grams

The theoretical mass of CO2 = 2.09 grams

The theoretical mass of H2O =  0.429 grams

The theoretical  mass of CO2+ H2O = 2.519 grams