All categories

3 years ago

I sold 6 coats for 60$ each. my commission is 20%, how much did I make? Explain please

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

If you sell 6 coat for 60$ each and you get 20% then you would get 72 in commission

You might be interested in

Show both decimal places (5.06).

lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

$c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6) \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62$

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

$c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9 \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9 \frac{1}{2} 2) = 1.66$

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

4 0

1 year ago

Find an equation of the plane through the point (−1,−5,−2)(−1,−5,−2) with normal vector n=⟨−5,−4,−1⟩n=⟨−5,−4,−1⟩.

Ostrovityanka [42]

Consider this option:
1. given: n(A;B;C)=n(-5;-4;-1) and A(-1;-5;-2)=A(x₀;y₀;z₀).
Common view of equation for a plane is Ax+By+Cz+D=0, where A,B,C,D - numbers.
2. from another side using coordinates of A and normal vector it is possible to make up the equation: A(x-x₀)+B(y-y₀)+C(z-z₀)=0 ⇒ -5(x+1)-4(y+5)-(z+2)=0; ⇒ -5x-4y-z-27=0 or 5x+4y+z+27=0.

7 0

3 years ago

(-2-4y)(-8) how do I solve ??

klasskru [66]

(-2-4y)(-8)
Use distributive property:
(-2*-8)+(-4y-8)
(remember that when 2 negative numbers are multiplied together it becomes positive.

16+32y

Hope this helps :)

3 0

3 years ago

Read 2 more answers

50 POINTS PLEASE HELP

Rainbow [258]

first simplify the numerator (x+3)(x-2)=x^2-2x+3x-6=x^2+x-6

now factor the numerator (x+3)(x-2)

now find the restriction 3x-6=0 3x=6 x=2

now factor the denominator 3(x-2)

((x+3)(x-2))/3(x-2)

now cross off the (x-2)

and you are left with (x+3)/3