The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
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Isolate the variable by dividing each side by factors that don’t contain the variable.
X = -2
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Answer:
Step-by-step explanation:
if there are 12 days and 500 bateria
60 days will be 12/60 times 500
that is 2500
Answer:
option c
SAS
Step-by-step explanation:
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