Answer:
A=πr2
A=π8^2
A=π* 8* 8
A= 64π
A= 64x3.14
A= 200.96 in^2
Step-by-step explanation:
Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
6x^2-x-2 this is of the form ax^2+bx+c
jk=ac=-12 and j+k=b=-1 so j and k must be -4 and 3 so
6x^2+3x-4x-2
3x(2x+1)-2(2x+1)
(3x-2)(2x+1)
