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mylen [45]
3 years ago
5

PLS HELP ASAP I MISSED THIS LESSON AND THIS IS DUE AT 11:59 THANK YOU

Mathematics
1 answer:
Nastasia [14]3 years ago
5 0

Answer:

x=8

Step-by-step explanation:

isn't that the same question

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Trevor picked 5 ⅗ pounds of cherries. He distributed them evenly into 12 containers. How many pounds of cherries were in each co
natulia [17]

Answer:

7/15

Step-by-step explanation:

For me, it is easier to take the 3/5 and put it in decimal form which is .6 and add the 5 to it, making 5.6, and then in a calculator put in 5.6 divided by 12 and you should get a big decimal that's pretty big but if you have a graphing calculator and convert that to a fraction and you should get 7/15, This is a pretty lazy way of me doing it but that's how I did it.

3 0
3 years ago
Write an expression showing the sum of 8 and a number .
77julia77 [94]

Answer:

8+ n

Step-by-step explanation:

my answer got delete so dont think i coped the person who did was user content bot

5 0
3 years ago
Some one please help me on this I am very much dum
AURORKA [14]
I don’t know this one either bro
4 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
fiasKO [112]

y = -\frac{1}{2}x - 1

Step-by-step explanation:

Let's pick two points on the line: P_1(-4, 1) and P_2(2, -2). Let's calculate the slope of this line using these points:

m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{-2 - 1}{2 - (-4)} = -\dfrac{1}{2}

With this value of the slope, we can write the general slope-intercept form of the equation as

y = -\frac{1}{2}x + b

To solve for the y-intercept b, let's use either P1 or P2. I'm going to use P2:

-2 = -\frac{1}{2}(2) + b \Rightarrow b = -1

Therefore, the slope-intercept form of the equation is

y = -\frac{1}{2}x - 1

6 0
2 years ago
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\


\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
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