1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

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<span>The weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 12. </span>
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Answer:
42 cm²
Step-by-step explanation:
The attachment shows a couple of ways the figure can be considered.
a) Left and Right rectangles that are 5 cm high and 3 cm wide, together with a central rectangle that is 3 cm high and 4 cm wide. Then the total area is ...
5×3 + 3×4 + 5×3 = 15 + 12 + 15 = 42 . . . . cm²
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b) An enclosing rectangle that is 5 cm high and 10 cm wide with a cut-out that is 2 cm high and 4 cm wide. Then the total area is ...
5×10 -2×4 = 50 -8 = 42 . . . . cm²
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The area of the irregular figure is 42 cm².
Answer:
Step-by-step explanation:
I think it is she sped up and passed susana since it shows it in the graph.
Answer:
q=3
Step-by-step explanation: