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3 years ago

ROBERT bought 2 packages of cookies for $6.00. How much would 3 packages of cookies cost?

Mathematics

1 answer:

babunello [35]3 years ago

5 0

Answer:

9.00$

Step-by-step explanation:

6 divided by 2 = 3 so each pakage cost 3$ so it would be 9.00$

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Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

5 0

3 years ago

3 x 2 1/2= ?????????????????/<br> Welp

igor_vitrenko [27]

Answer:15/2

Step-by-step explanation:

3 0

3 years ago

Find the limit as x approaches infinity of y=arccos(1+x21+2x2)y=arccos((1+x^2)/(1+2x^2))?

Katyanochek1 [597]

If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x approach infinity
lim y = arccos 1/2 = 1.047

6 0

3 years ago

What error did Clyde make? And what is the correct simplified form

romanna [79]

Answer:

Clyde added -8+(-2), your supposed to multiply -8*(-2) the answer is j^16

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If x=10^a , y=10^b and x^b.y^a=100.prove that xy=1

BabaBlast [244]

Answer:

ab=1

Step-by-step explanation:

Assuming that you meant ab=1

$x=10^{a}\\\\y=10^b\\\\x^b*y^a=100\\\\(10^a)^b*(10^b)^a=100\\\\10^{ab}*10^{ba}=100\\\\10^{ab+ba}=100\\\\10^{2ab}=100\\\\(10^2)^{ab}=100\\\\100^{ab}=100\\\\ab=1$ this is because the exponents have to be equal

8 0

3 years ago