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const2013 [10]
3 years ago
5

72, 12.2. common ratio

Mathematics
1 answer:
Ymorist [56]3 years ago
8 0

This problem is not solvable.

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What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3?
tresset_1 [31]
The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,

                                  Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
                                 S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96. 

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3 years ago
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Find the integral of sqrt(4x-x^2)dx.
lukranit [14]
∫ √(4x - x²) dx
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3 years ago
What the slope of (-15,9) (-10,3) ​​​
sweet [91]
The slope is - 3/10

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What is the classification for this polynomial?6
Fantom [35]

one term is monomial

two terms are binomials

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6 0
3 years ago
Calculate the distance between the points Q = (2, -1) and K = (6,-9) in the coordinate plane.
White raven [17]

Answer:

Sqrt 80 = 8.94

Step-by-step explanation:

d = sqrt[(x-x)^2 + (y-y)^2]

d = sqrt [(6-2)^2 + (-9 - - 1)^2]

d = sqrt [(4)^2 + (-8)^2]

d = sqrt (16 + 64)

d = sqrt 80

d = 4 sqrt 5 = 8.94

3 0
3 years ago
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