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3 years ago

Calcula el volumen en metros cúbicos de una piscina que tiene 8 m de largo 2 m de ancho y 1.5 m de profundidad

Mathematics

1 answer:

Stella [2.4K]3 years ago

7 0

Answer:

V = 24 m³

Step-by-step explanation:

The given question says that, 'Calculate the volume in cubic meters of a pool that is 8 m long, 2 m wide and 1.5 m deep'.

A pool is in the shape of a cubiod. The volume of the cuboid is given by :

V = lbh

Where

l is length, b is width and h is height

Put all the values,

V = 8 × 2 × 1.5

= 24 m³

So, the volume of the pool is equal to 24 m³.

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melomori [17]

Answer:

1/10

Step-by-step explanation:

There are three simple fractions in this problem: 3/5, -1/4 and 7/10. Rules of order require that the division (-1/4) divided by 7/10 be carried out first; the correct product is -10/28, or -5/14. Then we have 3/5 + (-5/14).

Here the LCD is 70. Then 3/5 + (-5/14) becomes 42/70 - 35/70, which simplifies to 1/10.

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rusak2 [61]

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3 years ago

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USPshnik [31]

Answer:

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Step-by-step explanation:

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3 years ago

Identify any x-intercepts for the graph below .

mylen [45]

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2 years ago

Xe^(-x^2/128) absolute max and absolute min

adoni [48]

$f(x)=xe^{-x^2/128}$
$\implies f'(x)=e^{-x^2/128}+x\left(-\dfrac{2x}{128}\right)e^{-x^2/128}=\left(1-\dfrac1{64}x^2\right)e^{-x^2/128}$

Extrema can occur when the derivative is zero or undefined.

$\left(1-\dfrac1{64}x^2\right)e^{-x^2/128}=0\implies 1-\dfrac1{64}x^2=0\implies x^2=64\implies x=\pm8$

Maxima occur where the first derivative is zero and the second derivative is negative; minima where the second derivative is positive. You have

$f''(x)=-\dfrac1{32}xe^{-x^2/128}+\left(1-\dfrac1{64}x^2\right)\left(-\dfrac{2x}{128}\right)e^{-x^2/128}=\left(-\dfrac3{64}x+\dfrac1{4096}x^3\right)e^{-x^2/128}$

At the critical points, you get

$f''(-8)=\dfrac1{4\sqrt e}>0$
$f''(8)=-\dfrac1{4\sqrt e}$

So you have a minimum at $\left(-8,-\dfrac8{\sqrt e}\right)$ and a maximum at $\left(8,\dfrac8{\sqrt e}\right)$ .

Meanwhile, as $x\to\pm\infty$ , it's clear that $f(x)\to0$ , so these extrema are absolute on the function's domain.

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3 years ago