You should have written like this
1 hour /16 = x hour /100
x=100/16=25/4=6.25
but it asks how many hours after first hour
6.25-1=5.25
Answer:
(6,0)
Step-by-step explanation:
The coordinates of the points dividing the line segment in ratio m:n can be calculated as:

Here x1, y1 are the coordinates of first point S (-2, -6) and x2, y2 are the coordinates of second point T(18, 9).
In this case m will be 2 and n will be 3 as the ratio is 2:3
Using all these values we can find the coordinates of point Q

Thus, the coordinates of point Q which divides the line segment ST in ratio of 2:3 are (6,0)
There are

ways of pairing up any 2 members from the pool of
contestants. Note that

so that

Which Statements?
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