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3 years ago

50 POINTS Which relation is a function of x? Look at the picture

Mathematics

2 answers:

muminat3 years ago

8 0

Answer:

The fourth one

Step-by-step explanation:

It has no repeating x's or y's

uysha [10]3 years ago

5 0

Answer:

Step-by-step explanation:

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Sasha Ruby and Mario each have 1 3 / 4 cups of flour.can they make a recipe for bread that needs 5 cups of flour

saw5 [17]

Each of them have 1 3/4 cups of flour, so together they have 2 x 1 3/4 cups. Turn the mixed number into an improper fraction in order to multiply it. 1 3/4 = 4/4 + 3/4 = 7/4. Multiply 7/4 x 2 = 7/4 x 2/1 = 7(2) / 4(1) = 14/4, which simplified equals 3 1/2 because 14/4 = 3 r2, or 3 2/4, which equals 3 1/2. So together they have a total of 3 1/2 cups of flour. Because 3 /12 is less than 5, they do not have enough cups of flour to make the recipe.

8 0

3 years ago

If AC equals 48 meters, what is the perimeter of the field

Alinara [238K]

Remark

A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)

Step One

Solve for AB

1/2 AC = 24 (AC is given as 48)

18 is a given length

AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30

Step Two

Find the length of AD

AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40

Step Three

Find the Perimeter.

P = 2 * 30 + 2*40 = 60 + 80 = 140

P = 140 <<<<< Answer

5 0

3 years ago

Read 2 more answers

My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the

AVprozaik [17]

Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use $\hat p =0.5$

$n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

8 0

3 years ago

The sum of two integers is -1. the product of the integers is -72 find the integers.

Elis [28]

$\left\{\begin{array}{ccc}x+y=-1\\x\ \times\ y=-72\end{array}\right\\\left\{\begin{array}{ccc}x=-y-1\\x\ \times\ y=-72\end{array}\right\\\\sunbstitute:\\\\(-y-1)y=-72\\-y^3-y+72=0\\\\a=-1;\ b=-1;\ c=72\\\Delta=b^2-4ac\to\Delta=(-1)^2-4\cdot(-1)\cdot72=1+288=289\\\\y_1=\frac{-b-\sqrt\Delta}{2a}\to y_1=\frac{1-\sqrt{289}}{2\cdot(-1)}=\frac{1-17}{-2}=\frac{-16}{-2}=8\\\\y_2=\frac{-b+\sqrt\Delta}{2a}\to y_2=\frac{1+\sqrt{289}}{2\cdot(-1)}=\frac{1+17}{-2}=\frac{18}{-2}=-9$

$
if\ y=8\ then\ x=-8-1=-9\\\\if\ y=-9\ then\ x=-(-9)-1=9-1=8\\\\Answer:8\ and\ -9.$

8 0

4 years ago

Read 2 more answers

∫∫x²(y-x)dxdy ,d là miền giới hạn bởi các đường y=x² và x=y²

Valentin [98]

It looks like the integral is

$\displaystyle \iint_D x^2 (y-x) \,\mathrm dx\,\mathrm dy$

where D is the set

D = {(x, y) : 0 ≤ x ≤ 1 and x ² ≤ y ≤ √x}

So we have

$\displaystyle \iint_D x^2(y-x)\,\mathrm dx\,\mathrm dy = \int_0^1 \int_{x^2}^{\sqrt x} x^2(y-x)\,\mathrm dy\,\mathrm dx \\\\ = \int_0^1 \left(\frac{x^2y^2}2-x^3y\right)\bigg|_{y=x^2}^{y=\sqrt x} \\\\ = \int_0^1 \left(\frac{x^3}2-x^{7/2}+x^5-\frac{x^6}2\right)\,\mathrm dx \\\\ = \left(\frac{x^4}8 - \frac{2x^{9/2}}9 + \frac{x^6}6 - \frac{x^7}{14}\right)\bigg|_{x=0}^{x=1} = \frac18-\frac29+\frac16-\frac1{14} = \boxed{-\frac{1}{504}}$

5 0

3 years ago