The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
1.A 2.D 3.B These are the answers I think is the choice to your question.
Answer:
y= - 5x+40
Step-by-step explanation:
I graphed this out. Remember that in parallel lines, the slopes are always the same.
Answer:
See below
Step-by-step explanation:
11 box 1: 12
11 box 2: 101
12 box 1: 80
12 box 2: 80
12 box 3: 80
13 box 1: 16
13 box 2: 16
13 box 3: 76
20 = y + 12
20 - 12 = y + 12 - 12
8 = y
x + 2 = 19
x + 2 - 2 = 19 - 2
x = 17
z - 313 = 176
z - 313 + 313 = 176 + 313
z = 489
In simplified form it is 5x+5
