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OverLord2011 [107]
3 years ago
15

Out of the 12 girls who tried out for the softball team, 10 will be chosen for the team. Find the number of different 10-person

teams
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

The answer is 66 ways .

Step-by-step explanation:

You have to use <u>Combination</u> because it says choosing 10 out of 12 as the position is not important :

12C10 = 66 ways of arrangements

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Josh has a piggy bank filled with coins. The number of dimes is three times the number of nickels. The number of nickels is five
slavikrds [6]

Answer:

nickels 15 dimes 45 pennies and quarters 10

8 0
3 years ago
Can someone explain (with steps) how to rationalize the following expression?
insens350 [35]
F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
(common denominator)
(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
(FOIL)
(-2-x^2-y^2-2xy+4)/(x+y-2)^(1/2)
(Distribute negative)
(-x^2-y^2-2xy+2)/(x+y-2)^(1/2)
(Simplify numerator)
(-x^2-y^2-2xy+2)(x+y-2)^(1/2)/(x+y-2)^(1/2)(x+y-2)^(1/2)
(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
(The function is now rational)
=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)
6 0
3 years ago
What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?
snow_tiger [21]

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

s34 = 6936/2

s34 = 3468 <=== the sum of the first 34 terms:

6 0
3 years ago
Ok this one is pearson realize if u know this help
makvit [3.9K]
There are 12 student(s) in the group, because there is 12 one-third part(s) in 4 while jars
7 0
2 years ago
Read 2 more answers
Giving Brainlies!! 14. How many tests did the student take during their junior year in high school? (1 point)
inessss [21]
Hi there.

The answer is definitely "D" because on the graph it shows there are only 29 students that did the test.

8 0
3 years ago
Read 2 more answers
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