<span>Given the two end of the diameter of the circle, we are able to compute the center of the circle as 0.5*[(-1,3)+(7,-7)]=(3,-2). The radius of the circle is 0.5*sqrt[(-1-7)^2+(3+7)^2]=sqrt(41). Therefore the equation of the circle is (x-3)^2+(y+2)^2=41.</span>
The 400th term is 425.There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are
![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 =
425.
Answer:
60
Step-by-step explanation:
You need the least common multiple of 5, 3, and 4.
5 = 5, 10, 15, 20, 25... 60
3= 3, 6, 9...60
4=4, 8, 12, ...60
Answer:
B
Step-by-step explanation:
One solution
The two (or more) equations would only intersect once
No solution
Lines never intersect
The lines are parallel
Infinite solutions
The lines are the exact same
That’s all the characteristics I know