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Drupady [299]
3 years ago
15

Analyze the diagram below and complete the instructions that follow. Find the values of x and y. Using those values, explain wha

t is wrong with the figure above.

Mathematics
2 answers:
denis-greek [22]3 years ago
3 0

I have not done that yet cause i'm only a sophomore.

Reptile [31]3 years ago
3 0

Answer:

The value of x is 12 and the value of y is 23. The given figure wrong because the vertically opposite angles are not same.

Step-by-step explanation:

From the given graph it is clear that lines XY and WZ intersect each other at point A and make 4 angles.

The angle XAZ and angle ZAY are supplementary angles because they lie on a straight line.

\angle XAZ+\angle ZAY=180

6x+35+8x-23=180

14x+12=180

14x=168

x=12

The value of x is 12.

The angle XAW and angle WAY are supplementary angles because they lie on a straight line.

\angle XAW+\angle WAY=180

3y+y+88=180

4y+88=180

4y=92

y=23

The value of y is 23.

The value of x is 12 and the value of y is 23, so the measure of all angles are

\angle XAZ=6x+35=6(12)+35=107

\angle ZAY=8x-23=8(12)-23=73

\angle XAW=3y=3(23)=69

\angle WAY=y+88=23+88=111

If two line intersect each other then the vertically opposite angles are always same. But here vertically opposite angles are not same.

\angle XAZ\neq \angle WAY

\angle ZAY\neq \angle XAW

Therefore the given figure wrong because the vertically opposite angles are not same.

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Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

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Imagine a right angled triangle with one of its acute angle as \theta .

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\sf\longrightarrow sin\theta =\dfrac{p}{h} \\

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And by Pythagoras theorem ,

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Where the symbols have their usual meaning.

Now , taking LHS ,

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\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\

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\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\

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Eben, an alien from the planet Tellurango, kicks a football from field level. The equation for the football’s height in meters,
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<span>The maxima of a differential equation can be obtained by getting the 1st derivate dx/dy and equating it to 0.</span>

<span>Given the equation h = - 2 t^2 + 12 t       , taking the 1st derivative result in:</span>

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h = -2 (3)^2 + 12 (3)

h = 18 m

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<span>The ball reaches a maximum height of 18 meters. The maximum of h(t) can be found both graphically or algebraically, and lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>

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We need to add the two terms.

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