The answer is -3. I just did it on a calculator
Answer:
slope is 1/3
Step-by-step explanation:
In between the points, you go up one, and forward 3. it can't be a negative slope cause it aint going down. And the slope of 3 is steep last time I checked.
Answer:
x2>y
Step-by-step explanation:
square is 2 and a number is x x2 and longer is another way for greater than another number witch is y
Answer:
y = −1/3x+17/3
Step-by-step explanation:
The line segment has slope -1/3. This means that any line perpendicular to it will have a slope of 3 (negative reciprocal)
Any line that bisects the line segment will pass through its midpoint. The midpoint is (5,4)
Midpoint formula: 
So perpendicular bisector of this line is simply a line with slope −1/3 that passes through point (5, 4)
y - 4 = -1/3 (x-5)=
y = −1/3x+17/3
Answer:
Eric
Step-by-step explanation:
First, we determine the distance of each player to the hole using the distance formula.
Given points 
Distance
<u>Eric</u>
The hole is at (3,2)
Eric's golf ball is at point (-6,6)
Distance=

<u>Cam</u>
The hole is at (3,2)
Cam's golf ball is at point (8,-6)
Distance=

<u>Brooke</u>
The hole is at (3,2)
Brooke's golf ball is at point (10,8)

Since Eric's ball is the farthest from the hole, Eric should shoot next.