Answer:
197×25)mm=4925
Step-by-step explanation:
multiply them v=lll
Answer:
Step-by-step explanation:
The figure required in the question is missing, the figure can be found in attachment.
Transforming points T and V according to the rule (x,y) -> (3/4x, 3/4y), we get:
T(-4, 8) -> (-4*3/4, 8*3/4) -> (-3, 6) which corresponds to T'
V(0, 4) -> (0*3/4, 4*3/4) -> (0, 3) which corresponds to V'
Answer:
Associative Property
Step-by-step explanation:
:)
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
3150 feet for both
Step-by-step explanation:
correct?
