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kolezko [41]
3 years ago
7

10. When a rubber ball is dropped from a height, h cm on to a flat concrete floor, it rebounds to 3 5 h cm a height of Given a r

ubber ball is dropped from a height of 120cm. Find a) the maximum height achieved by the ball after 2 bounces b) the total distance travelled by the ball when it hits the floor for 10 ^ m times. c) the total distance travelled by the ball if the ball continues to bounce in the same way indefinitely.​
Mathematics
1 answer:
Xelga [282]3 years ago
7 0

Step-by-step explanation:

Let the height above which the ball is released be H

This problem can be tackled using geometric progression.

The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is

To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H

a=2H..........r=3/4

However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H

Therefore the total distance travel up to the Nth bounce is

For N=3 one obtains

D=3.625H

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Hello,

Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)

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If you do'nt believe run this programm

DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
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3 years ago
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