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Ivan
3 years ago
14

For what value of b do the lines bx+3y=10 and x–2y=4 intersect at a point on the x-axis?

Mathematics
1 answer:
schepotkina [342]3 years ago
7 0
Since we need to find the point at which the 2 lines intersect at the x-axis, we need to find where the 2nd line intersects the x axis, by plugging in y=0.

x-2(0)=4
x=4
Therefore, at (4,0).

Now we plug in (4,0) at the first equation.
4b+3(0)=10
4b=10
b=5/2

Therefore, at b=5/2
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The Earth has a mass of about 6 x 1024 kg. Neptune has a mass of 1 x 1026 kg.
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Neptune is about four times wider than Earth.
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Find the mean, median, and mode for 0, 4, 6, 11, 9, 8, 9, 1, 5, 9, 7. Round to the nearest tenth if needed.
snow_lady [41]

Answer:

6

Step-by-step explanation:

you add them all up and divide it by how many numbers there are

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3 years ago
From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0
3 years ago
What are the solutions of the equation x^4-9x^2+8=0? Use u substitution to solve.
vodka [1.7K]

Answer:

The answer is the second option

Step-by-step explanation:

Let u=x^2.

( {x}^{2} ) {}^{2}  - 9( {x}^{2} ) + 8( {x}^{2} ) {}^{0}

{u}^{2}  - 9u + 8

(u - 1)(u - 8)

u = 1

u = 8

Set this equal to x^2

{x}^{2}  = 1

x = 1

or

x =  - 1

{x}^{2}  = 8

x = 2 \sqrt{2}

or

x =  - 2 \sqrt{2}

4 0
2 years ago
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