Answer:
Step-by-step explanation:
cartesian plane :
quadrant 1 : both x and y are positive
quadrant 2 : x is negative, y is positive
quadrant 3 : both x and y are negative
quadrant 4 : x is positive and y is negative
(-2,4)......we have x is negative and y is positive...so we are in quadrant 2
(3,-1)....we have x is positive and y is negative...in quadrant 4
(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x
(1,2)....both are positive....located in quadrant 1
(-3,-5)...both are negative.....quadrant 3
Answer:
Step-by-step explanation:
The picture of the question in the attached figure
we know that
----> by SOH (opposite side divided by the hypotenuse)
we have
solve for BC
substitute the values
<span>2/3 and 24/36 and 6/9
for 2/3 just dvide by 6, 24/36 just multiply both terms by 2 and for 6/9 just divide by 2</span>
M = -1/2
(x₁, y₁) = (-2,-4)
Find the equation
y - y₁ = m(x - x₁)
y - (-4) = -1/2 (x - (-2))
y + 4 = -1/2 (x + 2)
2(y + 4) = -1 (x + 2)
2y + 8 = -x - 2
x + 2y = -10
Answer:
answer = C
Step-by-step explanation:
