Please help picture shown !!!

What is the gcf of of -9y^2 + 6y

Valentin [98]

Answer:

3y

Step-by-step explanation:

First find the factors of the terms. You need to then figure out how many factors match.

-9y² = -1 · 3 · 3 · y · y

6y = 2 · 3 · y

3y is the greatest common factor.

5 0

4 years ago

The sand pit for the long jump has a width of 2.75 meters and a length of 9.54 meters. Just in case it rains, the principal want

iren2701 [21]

Answer:

nopooooentnj2kekrkrk3k3k3k3ii3i3i3i4i4i3

3 0

3 years ago

2. The Walton College of Business was ranked 24th out of all public business schools in the United States in 2005. The dean attr

Sholpan [36]

Answer:

See steps below

Step-by-step explanation:

a)

The null hypothesis is what is already established by previous researches

$\bf H_0:$ Business students average 6.8 hours/week studying.

the alternative hypothesis tries to see how accurate is this based on new evidence. Since the sample averaged 7.2 hours studying, this gives us a base to contrast the hypothesis.

$\bf H_a:$ Business students now average more than 6.8 hours/week studying.

As we can see, this is a right-tailed test.

b)

For a 0.05 significance level, the critical value is the value $\bf Z^*$ such that the area under the Normal curve N(0;1) to the right of $\bf Z^*$ is less than 0.05. This is a very well-known value that can be found by looking up a table or with the computer.

$\bf Z^*$ =1.64

If our z-statistic is greater or equal to 1.64 we have reasons to reject the null and accept the new average.

i.

Our z-statistic is given by the formula

$\bf z=\frac{\bar x - \mu}{\sigma/\sqrt{n}}$

where

$\bf \bar x$ is the mean of the sample

$\bf \mu$ is the mean of the null hypothesis

$\bf \sigma$ is the standard deviation

n is the sample size

Our z-statistic is then

$\bf z=\frac{7.2 - 6.8}{2.2/\sqrt{100}}=1.818181$

ii.

As we already said, our critical value is 1.64

iii.

Since our z-statistic is greater than the critical value, we reject the null hypothesis and accept 7.2 hours/week as the new average.

c)

The p-value for our statistic is the area under the Normal N(0;1) to the right of our z-statistic. (see picture attached).

This area can be calculated either with tables or computer-assisted and is 0.0345.

Comparing our p-value 0.0345 against the level of significance we see that

p-value < level of significance

Conclusion: when the p-value is less than the level of significance we can reject the null.

Remark:

Rejecting the null does not mean that the null is false or the alternative is true. It only means that the probability we had made a mistake by a random sampling error or other reason is less or equal than the p-value.