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CaHeK987 [17]
3 years ago
14

A package delivery service divides their packages into weight classes. suppose that packages in the 14 to 20 pound class are uni

formly distributed, meaning that all weights within that class are equally likely to occur. find the 40th percentile of packages weights in this weight class.
Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer: yy - \alpha \alpha = Percentile (\beta \beta -\alpha \alpha )

yy = 0.40 (20 - 14) + 14[tex] yy = 2.4 + 14

yy = 16.4

Thus, 16.4 pound class belongs to the 40th percentile of the weight class.

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I need help PLEASE.
bonufazy [111]
Notes: 
The notation ">=" without quotes means "greater than or equal to"
The upper case "U" means "set union"
Instead of using the intersection symbol, I will use a lower case 'n'

-------------------------------

Problem 1

A = {x | x < 1} which is the set of x values smaller than 1
B = {x | x >= 5} is the set of x values that are equal to 5 or larger
A U B = set of values that are from set A OR they are from set B (or both)
A U B = {x | x < 1 or x >= 5}
we simply connect the two inequalities mentioned with an "or" 

note: how there is no overlap between the two regions. The "U" means "set union" which is like a sort of glue to tie the two sets together with an "or". 

Answer: {x| x < 1 or x >= 5}
-------------------------------
Problem 2

A = {x | x < 1}
C = {x | x = 5} which is the set of one value only: 5 (x cannot equal any other value)
A U C = {x| x < 1 or x = 5}

So if a number is in set A U C, then this number is either less than 1, OR it is equal to 5

Answer: {x|x < 1 or x = 5}
-------------------------------
Problem 3

B U C = {x | x >= 5} because set C already has the "or equal to" part in there. 

Set C is a subset of set B. If an item is in set C, then it is also in set B.

Answer: {x| x >= 5}
-------------------------------
Problem 4

Again recall that I'm using an 'n' to indicate "set intersection" instead of the upside down "U" symbol

A n B is the set of items that are in BOTH sets A and B at the same time. From problem 1, I mentioned there's a gap. There is no x value that is both less than 1 AND greater than or equal to 5. So this means that

A n B = empty set

which we use the "O" with a slash through it. This is a special symbol to indicate "empty set"

Another way to write "empty set" is to use curly braces with nothing inside like so { } 

Answer: The "O" with a slash through it
-------------------------------
Problem 5

B n C is the same as {x| x = 5}

Why? Because if an item is in B n C, then it has to be in BOTH set B and set C at the same time. The only way this happens is if x = 5. If x is any other value, then it won't be in set C

Answer: {x| x = 5}
4 0
3 years ago
Use given triangle to fill in the blank.<br> PLEASE HELP ME!!!!!!!!!!!!!!!
lina2011 [118]

Answer:

b/c

Step-by-step explanation:

Sin B = opposite side/ hypotenuse = AC/AB

3 0
3 years ago
What is the midpoint between (-4 - 2i) and ( 6 + 8i) on the complex plane?
diamong [38]
Add the real parts and the imaginary parts separately and divide each by 2


= (  \frac{ - 4 + 6}{2}  +   \frac{ - 2i + 8i}{2} )


= ( \frac{2}{2}  +  \frac{6i}{2} )


=(1+3i)

5 0
3 years ago
A cone has a volume of 1570 cubic inches. Which of the following gives the volume of a cylinder with the same radius and same he
Hitman42 [59]

The volume of the cylinder is 4710 cubic inches

Step-by-step explanation:

Volume of the cone = 1570 cubic inches

Volume of cone = 1/3(volume of the cylinder)

So,

Volume of the cylinder = 3(volume of the cone)

Volume of the cylinder = 3(1570)

= 4710 cubic inches

The volume of the cylinder is 4710 cubic inches

3 0
3 years ago
Igualacion. <br><br>x-y=3. 2x-3y=4​
Delicious77 [7]

Answer:

x - y = 3

2x - 3y = 4

Igualación

Despejamos una de las incógnitas en cada ecuación e igualamos. (En este caso la x)

3y + 4

x = y + 3 x = ---------------

2

3y + 4

y + 3 = ---------------

2

2 (y + 3 ) = 3y + 4

2y + 6 = 3y + 4

se pasan las incógnitas a un lado y lo que cambia de lado se cambia de signo

3y - 2y = 6 - 4 ⇒ y = 2

sustituimos el valor de y en cualquiera de las dos para obtener el valor de x

x - 2 = 3 ⇒ x = 5

Solución

x = 5

y =2

4 0
3 years ago
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