The top and bottom faces are 3 inches by 3 inches.
Area = 3 in. * 3 in. * 2 = 18 in.^2
The front, back, right, and left faces are 3 in. by 6 in.
Area = 3 in. * 6 in. * 4 = 72 in.^2
Total surface area = 18 in.^2 + 72 in.^2 = 90 in.^2
Answer: B. 90 square inches
Answer:
a) Find the common ratio of this sequence.
Answer: -0.82
b) Find the sum to infinity of this sequence.
Answer: 2.2
Step-by-step explanation:
nth term in geometric series is given by ![4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{0.549} \\r = 0.82](https://tex.z-dn.net/?f=4%5C%20th%20%5C%20term%20%3D%20ar%5En-1%5C%5C-2.196%20%3D%204r%5E%7B4-1%7D%20%5C%5C-2.196%2F4%20%3D%20r%5E%7B3%7D%20%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B0.549%7D%20%5C%5Cr%20%3D%200.82)
where
a is the first term
r is the common ratio and
n is the nth term
_________________________________
given
a = 4
4th term = -2.196
let
common ratio of this sequence. be r
![4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{-0.549} \\r = -0.82](https://tex.z-dn.net/?f=4%5C%20th%20%5C%20term%20%3D%20ar%5En-1%5C%5C-2.196%20%3D%204r%5E%7B4-1%7D%20%5C%5C-2.196%2F4%20%3D%20r%5E%7B3%7D%20%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B-0.549%7D%20%5C%5Cr%20%3D%20-0.82)
a) Find the common ratio of this sequence.
answer: -0.82
sum of infinity of geometric sequence is given by = a/(1-r)
thus,
sum to infinity of this sequence = 4/(1-(-0.82) = 4/1.82 = 2.2
Answer:
X=4
Step-by-step explanation:
2X - 10 = -2
2X = 8
X = 8/2
X = 4
Best regards
Answer:
538.3
Step-by-step explanation:
First of all find the area of the rectangle
L*W
15*30
450
Now find the area of semi circle
1/2
Since radius is half a diameter divided 15 by 2=7.5
1/2
7.5 times 7.5= 56.25
1/2*3.14*56.25
56 times 3.14 is 176.625 now multiply 176.625 by 1/2
Answer is 88.3125
Now add 450 to 88.3125
Final answer: 538.3125