Answer: A)x²+x-6 B) 2x²-13
Step-by-step explanation: A) (x+3)(x-2)(x-8) = x²-2x+3x-6 = x²+x-6
B) (x+2)(x-2)(x+3)(x-3) =→ x²-2x+2x-4 = x²-4
→x²-3x+3x-9 = x²-9
∴x²-4+x²-9 = <u><em>2x²-13</em></u>
The third option because when you factor out the denominator, you get (x-1)(x+3), giving you zeros of 1 and -3
Answer:
- f¯¹(x) =9x+18, for the pictorial(image) question
- what is the send question is it asking derivative or inverse
- If it is inverse f¯¹(x)=-x-2 as it is
- Or if it is derivative f'(x)=-1
Step-by-step explanation:
<h2>
For the image question f(x)=1/9x-2,f¯¹(x)=?</h2>
- f(x)=1/9x-2............given
- y=1/9x-2................swapping f(x) by y to Easily write
- x=1/9y-2................interchanging x and y
- 1/9y-2=x................changeling side of equation
- 9(1/9y-2)=(x)9.......multiplying both sides by 9 to override the fraction on the right side
- y-18=9x
- y=9x-18.................Return to where it were
- <em><u>f¯¹(x)=9x+18</u></em>..........swap back f¯¹(x) in the y
<h2>
For the question f(x)=-x-2,f¯¹(x)=?</h2>
- following the ☝️ arrangement
- y=-x-2
- x=-y-2
- -y-2=x
- -y=x+2
- y=-x-2
- f¯¹(x)=-x-2
