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bixtya [17]
3 years ago
15

I need help with this.

Mathematics
1 answer:
ehidna [41]3 years ago
6 0

Answer:

A and b Are in quadrant 2. F and D are in quadrant 1. F is in quadrant 3 and C is in quadrant 4

Step-by-step explanation:

each quadrant is in the boxes and the question is asking what is each  coordinate is in what quadrant

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Multiply (5x^2-6x+2) x (4x^2-3x)
V125BC [204]

Answer:

20x^{4} - 39x^{3} + 26x^{2} - 6x

hope this helps

5 0
3 years ago
I will give brainliest for question! How many nonzero terms are in the expansion of (x+4)(2x^2+3x+9)-3(x^3-2x^2+7x)?
nataly862011 [7]

Answer:

Four

Step-by-step explanation:

Let's expand and see how many nonzero terms:

⇒ (x+4)(2x²+3x+9)-3(x³-2x²+7x)=

⇒ 2x³ + 3x² + 9x + 8x² + 12 + 36 - 3x³ + 6 x² - 21 x=

⇒ - x³ + 17x² - 12x + 12

As we see the expression has four nonzero terms

4 0
3 years ago
Four friends had dinner togethere.
nataly862011 [7]

Answer:

Your answer is $16.40

8 0
2 years ago
Which point lies on the circle represented by the equation (x+5) + (y-9) = 8
olga_2 [115]

Answer:

(-5,9+√8)

Step-by-step explanation:

There are two ways in which you can find a point that lies in the circle. One of them is to do y the subject of the formula, and another one is to determine the center of the circumference, and with the information of the radius, you can sum this value upward or downward.

the general equation of a circle is:

(x-h)^2+(y-k)^2=r^2

with center at (h,k)

you have the following equation:

(x+5)^2+(y-9)^2=8\\\\h=-5\\\\k=9\\\\r=\sqrt{8}

Then, the center is (-5,9)

if you sum the value of the radius in one of the fourth directions (up, down, left, right), for example upward you have

(-5,9+r)=(-5,9+\sqrt{8})

Then, one point that lies in the circle is (-5,9+√8)

3 0
3 years ago
What is the equation x^2+12x-3=16 written in the form (x-p)^2=q using the method of completing the square ?
Alexus [3.1K]

Step-by-step explanation:

{x}^{2}  + 12x -  3 = 16

{x}^{2}  + 12x = 19

{x}^{2}  + 12x + 36 = 19 + 36

(x + 6) {}^{2}  = 55

3 0
3 years ago
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