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devlian [24]
3 years ago
11

PLZ I NEED HELP!

Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

a. (6x-5)^2

b. 4x(2x^2+1)

c. -4(x-12)(x+3)

d. (2x+1)(4x-3)

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
21.60 divided by 1.35 is what?
klasskru [66]

Answer:

16

Step-by-step explanation:

21.60 divided by 1.35=16

8 0
3 years ago
Read 2 more answers
Which equation represents a parabola that has a focus of (0, 0) and a directrix of y = 2?
Genrish500 [490]

Answer: The correct answer is x^2=-4(y-1)

Step-by-step explanation:

Just took the test

7 0
3 years ago
I have no idea what the answers are
lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

2 = (2/3) 0 + b   => b = 2

Therefore    y = (2/3)x + 2

The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,-1) set x = 0, y= -1  in y = (2/3)x + b =>  

-1  = (2/3) 0 + b   => b = -1

Therefore    y = (2/3)x + -1

Thank you,

MrB

5 0
3 years ago
Find the distance between the points:
lesantik [10]
To calculate distance between two points we use the distance formula sqrt((x2−x1)^2+(y2−y1)^2).  

To start, we find the square of the distance between x1 and x2 and y1 and y2.  The distance between x1 and x2, or 1 and 3, is 2. The distance between y1 and y2, or 3 and -4, is 7.

Now we square 2 and 7 and add them together to get 4 + 49 = 53.

The last thing we do to find the distance is take the square root of 53. 53 is not a perfect square and is also a prime number so our answer in simplest form is still sqrt53.<span />
6 0
3 years ago
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