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devlian [24]
3 years ago
11

PLZ I NEED HELP!

Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

a. (6x-5)^2

b. 4x(2x^2+1)

c. -4(x-12)(x+3)

d. (2x+1)(4x-3)

Step-by-step explanation:

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A basketball has a diameter of 10 in. Using = 3.14, what is the approximate volume of the basketball in cubic inches?
m_a_m_a [10]

Answer:

523.3 cubic inches

Step-by-step explanation:

A basketball has a diameter of 10 in. Using = 3.14, what is the approximate volume of the basketball in cubic inches?

The shape of a basketball is spherical.

Hence:

The volume of a basketball = 4/3 × π × r³

From the question,

π = 3.14

r = radius = Diameter/2

r = 10 in/2 = 5 in

Hence:

The volume of the basketball

= 4/3 × 3.14 × 5³

= 1570 ÷ 3

= 523.33333333 cubic inches

Therefore, the approximate volume of the basketball = 523.3 cubic inches

5 0
3 years ago
I need help finding the intersection of the line and plane​
timofeeve [1]

Answer:

the line is making a kite like shape

5 0
3 years ago
Write at least three expressions that are equivalent to 3(2x - 5)
myrzilka [38]

Answer:

6x - 15

6x - (5 · 3)

(3 · 2x) - 15

6 0
3 years ago
Read 2 more answers
On a coordinate plane, a straight line and a parallelogram are shown. The straight line has a positive slope and has a formula o
Romashka [77]

9514 1404 393

Answer:

  (c)  (–5, 4)

Step-by-step explanation:

The rule for reflection across the line y=x is ...

  (x, y) ⇒ (y, x)

  G(4, -5) ⇒ G'(-5, 4)

6 0
3 years ago
A cone has radius 9 and height 12. A frustum of this cone has height 4.
Rom4ik [11]

The radii of the frustrum bases is 12

Step-by-step explanation:

In the figure attached below, ABC represents the cone cross-section while the BCDE represents frustum cross-section

As given in the figure radius and height of the cone are 9 and 12 respectively

Similarly, the height of the frustum is 4

Hence the height of the complete cone= 4+12= 16 (height of frustum+ height of cone)

We can see that ΔABC is similar to ΔADE

Using the similarity theorem

AC/AE=BC/DE

Substituting the values  

12/16=9/DE

∴ DE= 16*9/12= 12

Hence the radii of the frustum is 12  

3 0
3 years ago
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