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3 years ago

Classify the triangle as acute, right, or obtuse and as equilateral, isosceles, or scalene.

Mathematics

1 answer:

AlladinOne [14]3 years ago

8 0

9514 1404 393

Answer:

(d) Right, scalene

Step-by-step explanation:

The little square in the upper left corner tells you that is a right angle. Any triangle with a right angle is a right triangle. This one is scalene, because the sides are all different lengths.

Additional comment

An obtuse triangle cannot be equilateral, and vice versa.

An equilateral triangle has all sides the same length, and all angles the same measure: 60°. It is an acute triangle.

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What is 67,456 divided by 32 and tell me how

V125BC [204]

Answer:

2108

Step-by-step explanation:

Divide 67,456 by 32, using long division.

1) How many times 32 go into 67? (2 times, with a remainder of 3)

2) Bring down the 4.

3) How many times does 32 go into 34? (1 time, with a remainder of 2)

4) Bring down the 5

5) How many times does 32 go into 25? (0 times, so write 0)

6) Bring down the 6.

7) How many times does 32 go into 256? ( 8 times, no remainder)

8) Your answer is 2108

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3 years ago

Which function represents the following graph? X

IrinaVladis [17]

The last one because the other ones only go to the positive side and not the negative too since the cube root

3 0

2 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0

3 years ago

Harper’s Index claims that 23% of American are in favor of outlawing cigarettes. You decide to test this claim and ask a random

alexandr402 [8]

Answer:

There is enough evidence not to reject the claim.

Step-by-step explanation:

H0: The population proportion of Americans in favor of cigarette outlawing is 0.23.

Ha: The population proportion of Americans in favor of cigarette outlawing is not 0.23.

Critical value approach

z = (p' - p) ÷ sqrt[p(1 - p) ÷ n]

p' is sample proportion = 54/200 = 0.27

p is population proportion = 23% = 0.23

n is number of Americans sampled = 200

z = (0.27 - 0.23) ÷ sqrt[0.23(1 - 0.23) ÷ 300] = 0.04 ÷ sqrt[8.855×10^-4] = 0.04 ÷ 0.0298 = 1.34

The test is a two-tailed test because the alternate hypothesis is expressed using not equal to.

Critical value at 0.05 significance level is 1.96

For a two-tailed test, the region of no rejection of H0 lies between -1.96 and 1.96

Conclusion:

Fail to reject H0 because the test statistic 1.34 falls within the region bounded by -1.96 and 1.96.

There is enough evidence not to reject the claim because the claim is contained in the null hypothesis (H0).

8 0

3 years ago

Read 2 more answers

PLEASE HELPPPPPP!!!!! You are performing an experiment to determine how well plants grow under different light sources. Of the 3

PIT_PIT [208]

The probability that a plant in the experiment receives visible or ultraviolet light is 7/10.

Step-by-step explanation:

The total number of plants in the experiment = 30 plants

Plants that receive visible light alone = 12 plants

Plants that receive ultraviolet light alone = 15 plants

Plants that receive both visible and ultraviolet light = 6 plants

step 1 :

Probability = No. of required events / Total number

step 2 :

P(visible) = 12 / 30

P(ultraviolet) = 15 / 30

P(both) = 6 / 30

step 3 :

P(visible or ultraviolet) = P(visible) + P(ultraviolet) - P(both)

= 12/30 + 15/30 - 6/30

= 21/30

P(visible or ultraviolet) = 7/10

8 0

3 years ago

Classify the triangle as acute, right, or obtuse and as equilateral, isosceles, or scalene.​

Classify the triangle as acute, right, or obtuse and as equilateral, isosceles, or scalene.