What is the value of 5+5⋅34

An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou

Katyanochek1 [597]

Answer:

$t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17$

$p_v =P(t_{(5)}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation

The mean and sample deviation can be calculated from the following formulas:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}$

$\bar X=29.35$ represent the sample mean

$s=1.365$ represent the sample standard deviation

$n=6$ sample size

$\mu_o =30$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :

Null hypothesis: $\mu \geq 30$

Alternative hypothesis: $\mu < 30$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17$

P-value

We need to calculate the degrees of freedom first given by:

$df=n-1=6-1=5$

Since is a one-side left tailed test the p value would given by:

$p_v =P(t_{(5)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

5 0

2 years ago

Nonzero multiples of 16

Anna11 [10]

2 just 2 thats it♥♥

8 0

3 years ago

Pls help I’m failing asap

Kryger [21]

Answer:

The equation 2d + 18 = 24 can help find the number of days Jerry has been doing sit-ups.

Step-by-step explanation:

During the first day, Jerry did 18 sit-ups, and he proceeded to do 2 more sit-ups each following day, so the expression to represent this situation is 2d + 18. Because he did 24 sit-ups today, to find the number of days he did sit-ups, the equation to solve is 2d + 18 = 24.

4 0

2 years ago

What is the value of x?

Svetllana [295]

Answer:

x = 4

Step-by-step explanation:

ΔTRQ is an isosceles right triangle, so if we find the value of RT then the value of 'x' will be the same

We can find RT by creating a proportion based on the ratio of sides in a 30-60-90° triangle which, respectively, is 1 : $\sqrt{3}$ : 2

2 $\sqrt{3}$ /RT = $\sqrt{3}$ /2

cross-multiply:

$\sqrt{3}$ · RT = 4 $\sqrt{3}$

RT = 4

Therefore, x = 4

3 0

2 years ago

Jesse uses this expression to determine how much to pay, including tax and tip, when he goes out to a restaurant:

lana66690 [7]

Answer:

x is the price of the meal

(1+0.0825 + 0.18) is the total percentage on top of the price he pays with sales tax and tip.

Step-by-step explanation:

The factor x is the price of the meal. The factor (1 + 0.0825 + 0.18) is the 100% of the price, the sales tax on that price and the tip on the total. 1 + 0.0825 + 0.18 = 1.2625 is the total percentage he pays on the price. He pays 26.25% in addition of the price of the meal to cover tax and tip.

5 0

2 years ago